k^2=2(k+4)

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Solution for k^2=2(k+4) equation:


Simplifying
k2 = 2(k + 4)

Reorder the terms:
k2 = 2(4 + k)
k2 = (4 * 2 + k * 2)
k2 = (8 + 2k)

Solving
k2 = 8 + 2k

Solving for variable 'k'.

Reorder the terms:
-8 + -2k + k2 = 8 + 2k + -8 + -2k

Reorder the terms:
-8 + -2k + k2 = 8 + -8 + 2k + -2k

Combine like terms: 8 + -8 = 0
-8 + -2k + k2 = 0 + 2k + -2k
-8 + -2k + k2 = 2k + -2k

Combine like terms: 2k + -2k = 0
-8 + -2k + k2 = 0

Factor a trinomial.
(-2 + -1k)(4 + -1k) = 0

Subproblem 1

Set the factor '(-2 + -1k)' equal to zero and attempt to solve: Simplifying -2 + -1k = 0 Solving -2 + -1k = 0 Move all terms containing k to the left, all other terms to the right. Add '2' to each side of the equation. -2 + 2 + -1k = 0 + 2 Combine like terms: -2 + 2 = 0 0 + -1k = 0 + 2 -1k = 0 + 2 Combine like terms: 0 + 2 = 2 -1k = 2 Divide each side by '-1'. k = -2 Simplifying k = -2

Subproblem 2

Set the factor '(4 + -1k)' equal to zero and attempt to solve: Simplifying 4 + -1k = 0 Solving 4 + -1k = 0 Move all terms containing k to the left, all other terms to the right. Add '-4' to each side of the equation. 4 + -4 + -1k = 0 + -4 Combine like terms: 4 + -4 = 0 0 + -1k = 0 + -4 -1k = 0 + -4 Combine like terms: 0 + -4 = -4 -1k = -4 Divide each side by '-1'. k = 4 Simplifying k = 4

Solution

k = {-2, 4}

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